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A number when divided by 259 leaves a remainder 139. What will be the remainder when the same number is divided by 37?

Question

A number when divided by 259 leaves a remainder 139.

What will be the remainder when the same number is divided by 37?

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Solution

1. Break Down the Problem

We have a number N N that leaves a remainder of 139 when divided by 259. We need to find the remainder when N N is divided by 37.

2. Relevant Concepts

According to the division algorithm, we can express the number as: N=259k+139 N = 259k + 139 for some integer k k . To find the remainder of N N when divided by 37, we will calculate: Nmod37 N \mod 37

3. Analysis and Detail

Firstly, we need to compute 259mod37 259 \mod 37 : 259÷377(integer part) 259 \div 37 \approx 7 \quad \text{(integer part)} Calculating 7×37=259 7 \times 37 = 259 : So, 259mod37=0 259 \mod 37 = 0

Next, we find 139mod37 139 \mod 37 : 139÷373(integer part) 139 \div 37 \approx 3 \quad \text{(integer part)} Calculating 3×37=111 3 \times 37 = 111 : So, calculating the remainder: 139111=28 139 - 111 = 28 Thus, 139mod37=28 139 \mod 37 = 28

Now substituting back into our expression for N N : Nmod37=(259k+139)mod37=(0k+28)mod37=28 N \mod 37 = (259k + 139) \mod 37 = (0k + 28) \mod 37 = 28

4. Verify and Summarize

We confirmed that:

  • 259mod37=0 259 \mod 37 = 0
  • 139mod37=28 139 \mod 37 = 28

This leads us to conclude that when N N is divided by 37, the remainder is:

Final Answer

28 \boxed{28}

This problem has been solved

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