StudyGPT Just Leveled Up – Say Hello to Knowee! 🚀
Knowee
Questions
Features
Study Tools

On a temperature scale P, water freezes at −1600𝑃 and boils at  −500𝑃 . On this P scale,  a temperature of 340 K is

Question

🧐 Not the exact question you are looking for?Go ask a question

Solution

To solve this problem, we first need to understand the relationship between the Kelvin scale and the P scale. We know two points on both scales: the freezing point of water (0°C or 273.15K and -1600P) and the boiling point of water (100°C or 373.15K and -500P).

Step 1: Find the scale factor. The difference in temperature for water to go from freezing to boiling is the same in any scale. So, we can set up the equation:

(373.15K - 273.15K) / (-500P - (-1600P)) = 1

This simplifies to:

100K / 1100P = 1

So, 1P = 100K / 1100 = 0.0909K

Step 2: Find the zero point on the P scale. We know that 0K is absolute zero on the Kelvin scale, so we can find the equivalent on the P scale using the freezing point of water as a reference:

0K = -1600P + 273.15 * 0.0909

Solving for P gives us:

P = (0K + 1600P) / 0.0909 = -17624.24

Step 3: Convert 340K to the P scale. Now that we know the scale factor and the zero point, we can convert 340K to the P scale:

P = (340K + 1600P) / 0.0909 = -1500P

So, a temperature of 340K is equivalent to -1500P on the P scale.

This problem has been solved

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.