To find the power in the resistive network, we can use the formula P = V^2 * G, where P is the power, V is the voltage, and G is the conductance.

Given:
V = 30 V
G = 0.2 mS = 0.2 * 10^-3 S (since 1 mS = 10^-3 S)

Substituting these values into the formula:

P = (30)^2 * 0.2 * 10^-3
P = 900 * 0.2 * 10^-3
P = 180 * 10^-3
P = 0.18 W

Since 1 W = 1000 mW, we convert the power from W to mW:

P = 0.18 * 1000
P = 180

Question

To find the power in the resistive network, we can use the formula P = V^2 * G, where P is the power, V is the voltage, and G is the conductance.

Given:
V = 30 V
G = 0.2 mS = 0.2 * 10^-3 S (since 1 mS = 10^-3 S)

Substituting these values into the formula:

P = (30)^2 * 0.2 * 10^-3
P = 900 * 0.2 * 10^-3
P = 180 * 10^-3
P = 0.18 W

Since 1 W = 1000 mW, we convert the power from W to mW:

P = 0.18 * 1000
P = 180

Knowee AI · Accepted Answer

To find the power in the resistive network, we can use the formula P = V^2 * G, where P is the power, V is the voltage, and G is the conductance.

Given:
V = 30 V
G = 0.2 mS = 0.2 * 10^-3 S (since 1 mS = 10^-3 S)

Substituting these values into the formula:

P = (30)^2 * 0.2 * 10^-3
P = 900 * 0.2 * 10^-3
P = 180 * 10^-3
P = 0.18 W

Since 1 W = 1000 mW, we convert the power from W to mW:

P = 0.18 * 1000
P = 180

A resistive network consists of a conductance of 0.2 mS and a voltage source connected to the network is 30 V. What will be the power in mW?