How many mL of a 4.37 M NaBr solution are needed to make 515.46 mL of 2.25 M NaBr?

To solve this problem, you can use the formula M1V1 = M2V2, where M1 is the molarity of the initial solution, V1 is the volume of the initial solution, M2 is the molarity of the final solution, and V2 is the volume of the final solution.

Here's how you can solve it:

1. Identify the given values: M1 = 4.37 M (molarity of the initial NaBr solution) M2 = 2.25 M (molarity of the final NaBr solution) V2 = 515.46 mL (volume of the final NaBr solution)

2. Substitute the given values into the formula: (4.37 M)(V1) = (2.25 M)(515.46 mL)

3. Solve for V1: V1 = (2.25 M)(515.46 mL) / 4.37 M

4. Calculate the value of V1: V1 ≈ 267.97 mL

So, you would need approximately 267.97 mL of the 4.37 M NaBr solution to make 515.46 mL of a 2.25 M NaBr solution.