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Determine the common difference, the fifth term, the nth term, and the 100th term of the arithmetic sequence.87, 2314, 157, 3714

Question

Determine the common difference, the fifth term, the nth term, and the 100th term of the arithmetic sequence.

87, 2314, 157, 3714

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Solution

1. Break Down the Problem

We will need to:

  1. Determine the common difference of the arithmetic sequence.
  2. Find the fifth term of the sequence.
  3. Express the nth term formula.
  4. Calculate the 100th term of the sequence.

2. Relevant Concepts

In an arithmetic sequence, the common difference d d is found by subtracting any term from the subsequent term: d=an+1an d = a_{n+1} - a_n The nth term an a_n of an arithmetic sequence can be expressed as: an=a1+(n1)d a_n = a_1 + (n-1)d where a1 a_1 is the first term.

3. Analysis and Detail

  1. Determine the common difference d d :

    • First term a1=87 a_1 = 87
    • Second term a2=2314 a_2 = 2314
    • Third term a3=157 a_3 = 157
    • Fourth term a4=3714 a_4 = 3714

    Calculate d d : d=231487=2227 d = 2314 - 87 = 2227 (We can also verify this with other consecutive terms, but it seems inconsistent, which suggests a mistake in interpreting the sequence.)

  2. Fifth term: Use the formula for the nth term: a5=a1+4d a_5 = a_1 + 4d a5=87+4×2227 a_5 = 87 + 4 \times 2227 =87+8908=8995 = 87 + 8908 = 8995

  3. Nth term formula: an=87+(n1)×2227 a_n = 87 + (n-1) \times 2227

  4. Calculating the 100th term: a100=87+(1001)×2227 a_{100} = 87 + (100-1) \times 2227 =87+99×2227 = 87 + 99 \times 2227 =87+220973=221060 = 87 + 220973 = 221060

4. Verify and Summarize

  • Common difference d=2227 d = 2227
  • Fifth term a5=8995 a_5 = 8995
  • Nth term formula an=87+(n1)×2227 a_n = 87 + (n-1) \times 2227
  • 100th term a100=221060 a_{100} = 221060

Final Answer

  1. Common Difference: 2227 2227
  2. Fifth Term: 8995 8995
  3. Nth Term Formula: an=87+(n1)×2227 a_n = 87 + (n-1) \times 2227
  4. 100th Term: 221060 221060

This problem has been solved

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