An object weighs 10N in air. When immersed fully in water, it weighs only 8N. The weight of the liquid displaced by the object in standard units will be
Question
An object weighs 10N in air. When immersed fully in water, it weighs only 8N. The weight of the liquid displaced by the object in standard units will be
Solution
The weight of the liquid displaced by the object can be calculated using Archimedes' principle, which states that the buoyant force on an object immersed in a fluid is equal to the weight of the fluid displaced by the object.
In this case, the object weighs 10N in air and 8N in water. The difference in weight is due to the buoyant force exerted by the water on the object.
So, the weight of the water displaced by the object is equal to the difference in weight of the object in air and in water.
Weight of water displaced = Weight in air - Weight in water = 10N - 8N = 2N
Therefore, the weight of the water displaced by the object is 2N.
Similar Questions
A 10 kg ball weighs 98 N in air and weighs 75 N when submerged in water. The upward buoyant force on the ball is
An object weighs 43 N. It displaces 9 N of water. While in water, what is the object's weight? Input a whole number answer excluding the unit.
A 1.5 kg ball is floating in water. The volume of water displaced by the ball is
9.A raft of wood of mass 120kg floats in water. The weight that can be put on the raft to make it just sink should be (ρraft = 600kg/m3)
A wooden block of mass m tied to a string is attached to bottom of a vessel containing water and it is fully immersed. If buoyant force = 2 mg then
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.