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Create a dictionary where the keys are the indices and the values are the squares of the corresponding indices. The indices range from 0 to 9.

Question

Create a dictionary where the keys are the indices and the values are the squares of the corresponding indices. The indices range from 0 to 9.

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Solution

Sure, here is how you can create a dictionary in Python where the keys are the indices and the values are the squares of the corresponding indices. The indices range from 0 to 9.

# Initialize an empty dictionary
index_square_dict = {}

# Loop over the range of indices
for i in range(10):  # This will loop over numbers 0 to 9
    # Add the index and its square to the dictionary
    index_square_dict[i] = i ** 2

# Now, index_square_dict is a dictionary where the keys are the indices (0 to 9)
# and the values are the squares of the corresponding indices.

You can print the dictionary to check its contents:

print(index_square_dict)

This will output:

{0: 0, 1: 1, 2: 4, 3: 9, 4: 16, 5: 25, 6: 36, 7: 49, 8: 64, 9: 81}

This shows that the keys are the indices (0 to 9) and the values are the squares of the corresponding indices.

This problem has been solved

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