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An object of mass 5 kg is dropped from a height of 13 m. Determine the potential energy of the object.A

Question

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Solution

1. Break Down the Problem

To determine the potential energy (PE) of the object, we will:

  1. Identify the mass of the object.
  2. Identify the height from which the object is dropped.
  3. Use the formula for potential energy.

2. Relevant Concepts

The formula for gravitational potential energy is given by: PE=mgh PE = m \cdot g \cdot h where:

  • m m = mass of the object (in kilograms),
  • g g = acceleration due to gravity (approximately 9.81m/s2 9.81 \, \text{m/s}^2 ),
  • h h = height (in meters).

3. Analysis and Detail

  1. Given:

    • m=5kg m = 5 \, \text{kg}
    • h=13m h = 13 \, \text{m}
    • g=9.81m/s2 g = 9.81 \, \text{m/s}^2
  2. Substitute the values into the formula: PE=5kg×9.81m/s2×13m PE = 5 \, \text{kg} \times 9.81 \, \text{m/s}^2 \times 13 \, \text{m}

  3. Carry out the multiplication step by step:

    • Calculate 5×9.81=49.05kgm/s2 5 \times 9.81 = 49.05 \, \text{kg}\cdot\text{m/s}^2
    • Now calculate 49.05×13=637.65J 49.05 \times 13 = 637.65 \, \text{J}

4. Verify and Summarize

The calculations were performed step by step, and the operations are verified to be correct. The potential energy of the object is:

Final Answer

The potential energy of the object is 637.65J 637.65 \, \text{J} .

This problem has been solved

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