The balanced chemical equation is:

C3H8(g) + 5O2(g) → 3CO2(g) + 4H2O(g)

This equation tells us that 1 mole of C3H8 reacts to produce 3 moles of CO2.

So, if 2.00 moles of C3H8 are reacting, we can use a simple ratio to find out how many moles of CO2 are produced:

1 mole C3H8 produces 3 moles CO2
2 moles C3H8 would produce 2 * 3 = 6 moles CO2

So, 6 moles of CO2 are produced when 2.00 mol of C3H8 reacts with excess oxygen.

Question

The balanced chemical equation is:

C3H8(g) + 5O2(g) → 3CO2(g) + 4H2O(g)

This equation tells us that 1 mole of C3H8 reacts to produce 3 moles of CO2.

So, if 2.00 moles of C3H8 are reacting, we can use a simple ratio to find out how many moles of CO2 are produced:

1 mole C3H8 produces 3 moles CO2
2 moles C3H8 would produce 2 * 3 = 6 moles CO2

So, 6 moles of CO2 are produced when 2.00 mol of C3H8 reacts with excess oxygen.

Knowee AI · Accepted Answer

The balanced chemical equation is:

C3H8(g) + 5O2(g) → 3CO2(g) + 4H2O(g)

This equation tells us that 1 mole of C3H8 reacts to produce 3 moles of CO2.

So, if 2.00 moles of C3H8 are reacting, we can use a simple ratio to find out how many moles of CO2 are produced:

1 mole C3H8 produces 3 moles CO2
2 moles C3H8 would produce 2 * 3 = 6 moles CO2

So, 6 moles of CO2 are produced when 2.00 mol of C3H8 reacts with excess oxygen.

How many moles of CO2 are produced when 2.00 mol of C3H8 reacts with excess oxygen in the following reaction?C3H8(g) + 5O2(g)→3CO2(g) + 4H2O(g)