A 5 kg object is lifted 10 meters vertically upward. What is the work done against gravity? (Assume g=9.8m/s²)Select one:a.490 Jb.100 Jc.50 Jd.980 J

1. Break Down the Problem

To calculate the work done against gravity, we need to:

• Identify the force acting on the object (which is the weight of the object).
• Calculate the work done using the formula for work.

2. Relevant Concepts

The formula for work done $W$ against gravity is: $W = F \times d$ where:

• $F$ is the force (weight of the object) given by $F = m \times g$ (mass times acceleration due to gravity),
• $d$ is the distance moved in the direction of the force.

3. Analysis and Detail

1. Calculate the force (weight of the object):

   • Given:
     • Mass $m = 5 \, \text{kg}$
     • Gravitational acceleration $g = 9.8 \, \text{m/s}^2$
   • Calculate the weight $F$: $F = m \times g = 5 \, \text{kg} \times 9.8 \, \text{m/s}^2 = 49 \, \text{N}$

2. Calculate the work done:

   • Given:
     • Distance $d = 10 \, \text{m}$
   • Calculate work $W$: $W = F \times d = 49 \, \text{N} \times 10 \, \text{m} = 490 \, \text{J}$

4. Verify and Summarize

The calculations confirm that the work done against gravity is 490 J. The work done is verified through the multiplication of force and distance.

Final Answer

The work done against gravity is 490 J (Option a).