If the temperature of a gas is 27C and is changed so that the volume of the gas quadruple its initial volume what is the new temperatur

To solve this problem, we can use Charles's Law, which states that the volume of a gas is directly proportional to its temperature, provided the pressure and the amount of gas remain constant. The formula for Charles's Law is V1/T1 = V2/T2, where:

• V1 is the initial volume
• T1 is the initial temperature
• V2 is the final volume
• T2 is the final temperature

Given in the problem:

• V1 = 1 (we can assume the initial volume is 1 for simplicity, as we're interested in the change in volume)
• T1 = 27°C. However, temperatures in Charles's Law need to be in Kelvin, so we convert this to Kelvin by adding 273.15, giving us T1 = 300.15 K.
• V2 = 4 (the volume quadruples)

We're solving for T2, the final temperature. Substituting the known values into the formula gives us:

1/300.15 = 4/T2

Solving for T2 gives us:

T2 = 4 * 300.15

T2 = 1200.6 K

However, the problem asks for the temperature in Celsius, so we convert this back by subtracting 273.15:

T2 = 1200.6 - 273.15

T2 = 927.45°C

So, the new temperature of the gas, when the volume is quadrupled, is approximately 927.45°C.