The sum of ages of 5 children born at the intervals of 3 years each is 50 years. Find out the age of the youngest child?Options6 years4 years3 years5 years
Question
The sum of ages of 5 children born at the intervals of 3 years each is 50 years. Find out the age of the youngest child?
Options:
- 6 years
- 4 years
- 3 years
- 5 years
Solution
Let's solve this step by step:
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We know that the sum of the ages of the 5 children is 50 years.
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The children were born at intervals of 3 years each. This means that if the youngest child is x years old, the next child is x+3 years old, the child after that is x+6 years old, and so on.
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Therefore, we can express the sum of their ages as follows: x + (x+3) + (x+6) + (x+9) + (x+12) = 50
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Simplifying the left side of the equation gives: 5x + 30 = 50
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Subtract 30 from both sides to isolate the term with x: 5x = 50 - 30, which simplifies to 5x = 20
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Finally, divide both sides by 5 to solve for x: x = 20 / 5, which simplifies to x = 4
Therefore, the youngest child is 4 years old.
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