The surface tension of water is 0.0730 N/m. What is the height of the water in a capillary tube of diameter 2.00 mm?

To solve this problem, we will use the formula for capillary rise which is given by:

h = 2Tcos(θ)/ρgd

where: h = height of the water in the capillary tube T = surface tension of the water θ = contact angle (for water, it is approximately 0 degrees) ρ = density of the water (approximately 1000 kg/m^3) g = acceleration due to gravity (approximately 9.81 m/s^2) d = diameter of the capillary tube

Given: T = 0.0730 N/m d = 2.00 mm = 2.00 x 10^-3 m (since 1 m = 1000 mm)

Substituting the given values into the formula:

h = 2(0.0730 N/m)cos(0)/(1000 kg/m^3 * 9.81 m/s^2 * 2.00 x 10^-3 m)

Solving the above equation will give us the height of the water in the capillary tube.