Specific heat capacity of water is 4200 J/kg⁰C. How much energy is needed to raise thetemperature of 3kg of water by 4⁰C?
Question
Specific heat capacity of water is 4200 J/kg⁰C. How much energy is needed to raise the temperature of 3kg of water by 4⁰C?
Solution
To calculate the energy needed to raise the temperature of a certain amount of water, we can use the formula:
Q = mcΔT
where:
- Q is the heat energy (in Joules)
- m is the mass of the substance (in kg)
- c is the specific heat capacity (in J/kg°C)
- ΔT is the change in temperature (in °C)
Given:
- m = 3 kg
- c = 4200 J/kg°C
- ΔT = 4°C
Substitute these values into the formula:
Q = 3 kg * 4200 J/kg°C * 4°C = 50400 J
So, 50400 Joules of energy is needed to raise the temperature of 3 kg of water by 4°C.
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