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The length of a rectangle is five times its width.If the area of the rectangle is 320 ft2, find its perimeter.

Question

The length of a rectangle is five times its width.

If the area of the rectangle is 320 ft², find its perimeter.

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Solution

Sure, let's solve this step by step.

Step 1: Let's denote the width of the rectangle as x. Therefore, the length of the rectangle is 5x.

Step 2: The area of a rectangle is calculated by multiplying its length by its width. So, we can set up the equation: x * 5x = 320 ft².

Step 3: Simplify the equation to 5x² = 320.

Step 4: Divide both sides of the equation by 5 to solve for x². x² = 320/5 = 64.

Step 5: Take the square root of both sides to solve for x. x = √64 = 8 ft.

Step 6: Now that we know the width (x), we can find the length by multiplying the width by 5. So, the length is 5 * 8 = 40 ft.

Step 7: The perimeter of a rectangle is calculated by adding up all its sides. So, the perimeter is 2*(length + width) = 2*(40 ft + 8 ft) = 96 ft.

So, the perimeter of the rectangle is 96 ft.

This problem has been solved

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