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If  α, β  are zeros of  ax2 + bx + c, ac  ≠  0 , then zeros of  cx2 + bx + a  are Select an answerA −α, −β B α, 1β C β, 1α D 1α, 1β

Question

If  α, β are zeros of  ax2 + bx + c, ac  ≠  0, then zeros of  cx2 + bx + a are

Select an answer
A −α, −β
B α, 1β
C β, 1α
D 1α, 1β

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Solution

Given that α, β are the zeros of the quadratic equation ax² + bx + c = 0, we know that:

α + β = -b/a (Sum of the roots) αβ = c/a (Product of the roots)

Now, we are asked to find the zeros of the quadratic equation cx² + bx + a = 0.

Let's denote the zeros of this equation as p and q. Then, we have:

p + q = -b/c (Sum of the roots) pq = a/c (Product of the roots)

Comparing these with the sum and product of the roots of the first equation, we can see that:

p + q = α + β pq = αβ / c

This implies that the roots of the second equation are the reciprocals of the roots of the first equation. Therefore, the zeros of the equation cx² + bx + a = 0 are 1/α and 1/β.

So, the correct answer is D: 1/α, 1/β.

This problem has been solved

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