How many moles of isooctane must be burned to produce 100 kJ of heat under standard state conditions?

To determine the number of moles of isooctane that must be burned to produce 100 kJ of heat under standard state conditions, we can use the concept of molar enthalpy of combustion.

1. First, we need to find the molar enthalpy of combustion of isooctane. This value represents the amount of heat released when one mole of isooctane is completely burned. Let's assume the molar enthalpy of combustion of isooctane is -5500 kJ/mol.

2. Next, we can use the equation:

   Heat released = Number of moles * Molar enthalpy of combustion

   Rearranging the equation, we have:

   Number of moles = Heat released / Molar enthalpy of combustion

   Plugging in the values, we get:

   Number of moles = 100 kJ / -5500 kJ/mol

3. Now, we can calculate the number of moles:

   Number of moles = -0.0182 mol

Therefore, approximately 0.0182 moles of isooctane must be burned to produce 100 kJ of heat under standard state conditions.