In a binary multiplier, how many partial products are generated when multiplying two n-bit binary numbers? Question 2Answera.2n b.n c.n^2 d.2^n

The number of partial products in a binary multiplier when multiplying two n-bit binary numbers is n^2. So, the correct answer is c. n^2.

Here's why:

In a binary multiplication operation, each bit of the multiplier is multiplied with the multiplicand to generate a partial product. If there are n bits in the multiplier, there will be n partial products.

However, each partial product is itself an n-bit number (assuming we're padding with zeros for the less significant bits). Therefore, in total, we have n * n = n^2 bits in all the partial products combined.

So, the number of partial products generated when multiplying two n-bit binary numbers in a binary multiplier is n^2.