Find the value of each expression if 3 is substituted for a.a a + 4 b a + 6 c 7 + a d a + 20<***dia***>e a + 100 f 1000 + a g a + 200 h a + 10 000

To solve this expression with $a = 3$, we will substitute $3$ for all occurrences of $a$ and simplify each term:

Step 1: Substitute $a$ with $3$

1. $aa$ becomes $3 \times 3 = 9$
2. $a + 4$ becomes $3 + 4 = 7$
3. $ba + 6$ becomes $b \times 3 + 6$
4. $7 + a$ becomes $7 + 3 = 10$
5. $da + 20$ becomes $d \times 3 + 20$
6. $<\text{dia}>$ remains unknown without clarification
7. $ea + 100$ becomes $e \times 3 + 100$
8. $f$ remains as $f$ with no substitution applied
9. $1000 + a$ becomes $1000 + 3 = 1003$
10. $ga + 200$ becomes $g \times 3 + 200$
11. $ha + 10,000$ becomes $h \times 3 + 10,000$

Step 2: Final Expressions

The results of substituting $a = 3$ lead to the following expressions:

• $9$ for $aa$
• $7$ for $a + 4$
• $3b + 6$ for $ba + 6$
• $10$ for $7 + a$
• $3d + 20$ for $da + 20$
• $<\text{dia}>$ remains unresolved.
• $3e + 100$ for $ea + 100$
• $1003$ for $1000 + a$
• $3g + 200$ for $ga + 200$
• $3h + 10,000$ for $ha + 10,000$

Final Answer

The substituted values are:

• $aa = 9$
• $a + 4 = 7$
• $ba + 6 = 3b + 6$
• $7 + a = 10$
• $da + 20 = 3d + 20$
• $ea + 100 = 3e + 100$
• $1000 + a = 1003$
• $ga + 200 = 3g + 200$
• $ha + 10,000 = 3h + 10,000$

The expression $<\text{dia}>$ remains to be clarified for further evaluation.