What will be the output of the above Python code?d1={"abc":5,"def":6,"ghi":7}print(d1[0])abc5{"abc":5}Error
Question
Solution 1
The output of the above Python code will be an Error.
In Python, dictionaries are accessed by keys and not by index. So when you try to access the dictionary 'd1' with an index '0', Python will throw a KeyError as '0' is not a key in the dictionary.
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