What will be the output of the above Python code?d1={"abc":5,"def":6,"ghi":7}print(d1[0])abc5{"abc":5}Error
Question
What will be the output of the above Python code?
d1 = {"abc": 5, "def": 6, "ghi": 7}
print(d1[0])
- abc
- 5
- {"abc": 5}
- Error
Solution
The output of the above Python code will be an Error.
In Python, dictionaries are accessed by keys and not by index. So when you try to access the dictionary 'd1' with an index '0', Python will throw a KeyError as '0' is not a key in the dictionary.
Here is the step by step explanation:
-
A dictionary 'd1' is defined with keys "abc", "def", "ghi" and corresponding values 5, 6, 7.
-
The print statement tries to print the value of the key '0' in the dictionary 'd1'.
-
Since there is no key '0' in the dictionary 'd1', Python throws a KeyError.
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