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YouA police chases a thief. Their respective speeds are 8 and 6 km/hr. If the police started 10 min late, at what distance he will catch the thief

Question

A police chases a thief. Their respective speeds are 8 and 6 km/hr. If the police started 10 min late, at what distance will he catch the thief?

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Solution

Sure, let's solve this step by step:

Step 1: Convert the time the police started late from minutes to hours. 10 minutes = 10/60 = 0.167 hours

Step 2: Calculate the distance the thief has covered in the time the police started late. Distance = Speed x Time Distance = 6 km/hr x 0.167 hr = 1 km

Step 3: Now, the police and the thief are 1 km apart. The police is faster than the thief by 2 km/hr (8 km/hr - 6 km/hr).

Step 4: Calculate the time it will take for the police to catch up with the thief. Time = Distance / Speed Time = 1 km / 2 km/hr = 0.5 hours

Step 5: Convert this time to distance for the police. Distance = Speed x Time Distance = 8 km/hr x 0.5 hr = 4 km

So, the police will catch the thief 4 km from the point the police started.

This problem has been solved

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