YouA police chases a thief. Their respective speeds are 8 and 6 km/hr. If the police started 10 min late, at what distance he will catch the thief
Question
A police chases a thief. Their respective speeds are 8 and 6 km/hr. If the police started 10 min late, at what distance will he catch the thief?
Solution
Sure, let's solve this step by step:
Step 1: Convert the time the police started late from minutes to hours. 10 minutes = 10/60 = 0.167 hours
Step 2: Calculate the distance the thief has covered in the time the police started late. Distance = Speed x Time Distance = 6 km/hr x 0.167 hr = 1 km
Step 3: Now, the police and the thief are 1 km apart. The police is faster than the thief by 2 km/hr (8 km/hr - 6 km/hr).
Step 4: Calculate the time it will take for the police to catch up with the thief. Time = Distance / Speed Time = 1 km / 2 km/hr = 0.5 hours
Step 5: Convert this time to distance for the police. Distance = Speed x Time Distance = 8 km/hr x 0.5 hr = 4 km
So, the police will catch the thief 4 km from the point the police started.
Similar Questions
A and B take part in 100 m race. A runs at 5 kmph. A gives B a start of 8 m and still beats him by 8 seconds. The speed of B is:
Walking with 6/7th of his usual speed , Prakash was late by 12 minutes . What is the usual time taken by Prakash to cover the distance ?
Select the correct answerA man crosses a street 600 meters long in 5 minutes. His speed in kilometers per hour is:Options2.67.23.610
Walking at 60% of his usual speed, a man reaches his destination 1 hour 40 minutes late. His usual time (In hours) to reach the destination is?
7) Walking at 5/6 of its usual speed, a train is 10 minutes too late. Find its usual time to cover the journey.
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.