Determine the concentration of nitrate ions in 0.500 cm3 of 0.600 mol dm–3 of Fe(NO3)3 solution.

To determine the concentration of nitrate ions in the given solution, we need to understand the chemical formula of iron(III) nitrate: Fe(NO3)3. This tells us that there are three nitrate ions (NO3-) for every one iron(III) nitrate molecule.

1. First, we need to convert the volume of the solution from cm3 to dm3 because the concentration is given in mol/dm3. There are 1000 cm3 in 1 dm3, so 0.500 cm3 = 0.000500 dm3.

2. The concentration of Fe(NO3)3 is given as 0.600 mol/dm3. This means that there are 0.600 moles of Fe(NO3)3 in every dm3 of the solution.

3. To find the number of moles of Fe(NO3)3 in our 0.000500 dm3 of solution, we multiply the volume by the concentration: 0.000500 dm3 * 0.600 mol/dm3 = 0.000300 mol.

4. Since there are three nitrate ions for every molecule of Fe(NO3)3, the number of moles of nitrate ions is three times the number of moles of Fe(NO3)3: 0.000300 mol * 3 = 0.000900 mol.

5. Finally, to find the concentration of nitrate ions, we divide the number of moles by the volume of the solution in dm3: 0.000900 mol / 0.000500 dm3 = 1.80 mol/dm3.

So, the concentration of nitrate ions in the solution is 1.80 mol/dm3.