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A car travels from point A to point B at a speed of 60 mph and returns to point A at a speed of 80 mph. What is the average speed for the round trip?

Question

A car travels from point A to point B at a speed of 60 mph and returns to point A at a speed of 80 mph. What is the average speed for the round trip?

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Solution

To find the average speed for the round trip, we need to consider the total distance traveled and the total time taken for the trip. Here are the steps to solve the problem:

  1. Define the variables:

    • Let d d be the distance from point A to point B.
    • The speed from A to B is 60 mph.
    • The speed from B to A is 80 mph.
  2. Calculate the time taken for each leg of the trip:

    • Time taken to travel from A to B: t1=d60 t_1 = \frac{d}{60} hours.
    • Time taken to travel from B to A: t2=d80 t_2 = \frac{d}{80} hours.
  3. Calculate the total distance traveled:

    • The total distance for the round trip is 2d 2d .
  4. Calculate the total time taken for the round trip:

    • The total time is t1+t2=d60+d80 t_1 + t_2 = \frac{d}{60} + \frac{d}{80} .
  5. Find a common denominator to add the times:

    • The common denominator of 60 and 80 is 240.
    • Convert the times to have the same denominator: d60=4d240 \frac{d}{60} = \frac{4d}{240} d80=3d240 \frac{d}{80} = \frac{3d}{240}
    • Add the times: t1+t2=4d240+3d240=7d240 t_1 + t_2 = \frac{4d}{240} + \frac{3d}{240} = \frac{7d}{240}
  6. Calculate the average speed:

    • The average speed is the total distance divided by the total time: Average speed=Total distanceTotal time=2d7d240 \text{Average speed} = \frac{\text{Total distance}}{\text{Total time}} = \frac{2d}{\frac{7d}{240}}
    • Simplify the expression: Average speed=2d×2407d=480d7d=480768.57 mph \text{Average speed} = 2d \times \frac{240}{7d} = \frac{480d}{7d} = \frac{480}{7} \approx 68.57 \text{ mph}

So, the average speed for the round trip is approximately 68.57 mph.

This problem has been solved

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