100g of a diatomic molecule, Z2, reacts with water to form 74 .0 g of ZOH and 51.4 g of ZH. Calculate the relative atomic mass and hence the identity of Z.
Question
100g of a diatomic molecule, Z2, reacts with water to form 74.0 g of ZOH and 51.4 g of ZH.
Calculates the relative atomic mass and hence the identity of Z.
Solution
To solve this problem, we need to use the law of conservation of mass which states that matter cannot be created or destroyed.
Step 1: Calculate the mass of Z in Z2 The mass of Z2 is 100g. Since it's a diatomic molecule, it means it's made up of two atoms of Z. Therefore, the mass of Z in Z2 is 100g/2 = 50g.
Step 2: Calculate the mass of Z in ZOH and ZH The mass of Z in ZOH is 74.0g - mass of O - mass of H. The atomic masses of O and H are approximately 16g and 1g respectively. Therefore, the mass of Z in ZOH is 74.0g - 16g - 1g = 57g. The mass of Z in ZH is 51.4g - mass of H = 51.4g - 1g = 50.4g.
Step 3: Calculate the average mass of Z The average mass of Z is (mass of Z in Z2 + mass of Z in ZOH + mass of Z in ZH) / 3 = (50g + 57g + 50.4g) / 3 = 52.47g.
Step 4: Identify Z The relative atomic mass of Z is approximately 52.47, which is close to the atomic mass of chromium (Cr), 52. Therefore, Z is chromium (Cr).
Similar Questions
A certain sample of element Z contains 60% of 69Z and 40% of 71Z. What is the relative atomic mass ofelement Z in this sample?A. 69.2B. 69.8C. 70.0D. 70.2
The mass of 6 million molecules of a diatomic gas is 5.1 × 10-19 kg. What is the atomic mass of the element in this gas?
2.0 grams of Zn reacts with excess oxygen to produce ZnO. What is the mass of ZnO produced?2019 Atomi QuestionA(Choice A)
What is the mass in kg of 4.02 x 102 mol K2Cr2O7?Question 4Select one:a.1.18 x 105 kgb.1.18 x 102 kgc.1.37 x 10-3 kgd.1.37 x 10-6 kge.1.18 kg
Calculate the number of moles of 70.0 g of NaOH. Molar mass of NaOH is 40.0 g/mol
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.