When CH3NH2 is treated with HCl, one of the products is Cl−. Draw the other product.
Question
Solution 1
When CH3NH2 (methylamine) is treated with HCl (hydrochloric acid), it forms a salt. The reaction can be written as follows:
CH3NH2 + HCl -> CH3NH3+ + Cl-
So, the other product is CH3NH3+ (methylammonium ion).
To draw the structure of CH3NH3+:
- Start by drawing a Nitrogen (N) atom in the cente Knowee AI is a powerful AI-powered study tool designed to help you to solve study problem.
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