If 3a2 - (a - 7) + [-4(a2 - 9) + 4a] is equivalent to pa2 + qa + r, then what is the value of 5p + 3q - r?
Question
Solution 1
First, let's simplify the given expression 3a^2 - (a - 7) + [-4(a^2 - 9) + 4a].
This simplifies to 3a^2 - a + 7 - 4a^2 + 36 + 4a.
Combine like terms to get -a^2 + 3a + 43.
So, we have -a^2 + 3a + 43 = pa^2 + qa + r.
Comparing the coefficients, we get:
p = -1, q = 3, and r = 43.
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