The product of two numbers is 4107. If the H.C.F. of these numbers is 37, then the greater number is:
Question
The product of two numbers is 4107. If the H.C.F. of these numbers is 37, then the greater number is:
Solution
Step 1: We know that the product of two numbers is equal to the product of their H.C.F. and L.C.M.
So, let's denote the two numbers as a and b, their H.C.F. as h and their L.C.M. as l. We have:
a * b = h * l
Step 2: We are given that a * b = 4107 and h = 37. We can substitute these values into the equation:
4107 = 37 * l
Step 3: Solve for l:
l = 4107 / 37 = 111
Step 4: Now we know that the numbers a and b are factors of 4107 that also have a H.C.F. of 37. Since 37 is a factor of 4107, the other factors will be 37 and 111.
Step 5: Therefore, the greater number is 111.
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