Find the indicated intercept(s) of the graph of the function. f(x) = (x-3)/(x^2 + 2x -3)

To find the intercepts of the function f(x) = (x-3)/(x^2 + 2x -3), we need to find the x-intercept and the y-intercept.

1. X-intercept: The x-intercept is the value of x when f(x) = 0. So, we set the function equal to zero and solve for x.

   0 = (x-3)/(x^2 + 2x -3)

   This implies that the numerator of the fraction must be zero (since zero times anything is zero). So, we set x - 3 = 0 and solve for x.

   x - 3 = 0 x = 3

   So, the x-intercept is 3.

2. Y-intercept: The y-intercept is the value of f(x) when x = 0. So, we substitute x = 0 into the function and solve for f(x).

   f(0) = (0-3)/(0^2 + 2*0 -3) = -3/-3 = 1

   So, the y-intercept is 1.

Therefore, the intercepts of the function are x = 3 and y = 1.