Find the distance between the points (–5,3) and (–5,10).-10-8-6-4-2246810-10-8-6-4-22468100xy(–5,10)(–5,3)Round decimals to the nearest tenth.
Question
Find the distance between the points (–5,3) and (–5,10).
-10 -8 -6 -4 2 2 4 6 8 10 -10 -8 -6 -4 2 2 4 6 8 10
xy
(–5,10)
(–5,3)
Round decimals to the nearest tenth.
Solution
The distance between two points in a plane with coordinates (x1, y1) and (x2, y2) is given by the formula:
d = sqrt[(x2-x1)² + (y2-y1)²]
In this case, the points are (–5,3) and (–5,10).
The x-coordinates are the same, so (x2-x1)² = 0.
The difference in y-coordinates is 10 - 3 = 7.
So, the distance is sqrt[0 + 7²] = sqrt[49] = 7.
Therefore, the distance between the points (–5,3) and (–5,10) is 7 units.
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