2. A kettle containing water at 30 °C is heated to 100°C. Find the change in temperature in: i) °C ii) K​

1. Break Down the Problem

We need to find the change in temperature when water is heated from $30 \, \text{°C}$ to $100 \, \text{°C}$. This involves two parts: i) Calculate the change in temperature in degrees Celsius (°C).
ii) Calculate the change in temperature in kelvins (K).

2. Relevant Concepts

• The change in temperature in degrees Celsius is calculated using the formula: $\Delta T(°C) = T_{\text{final}} - T_{\text{initial}}$
• The change in temperature in kelvins is numerically equal to the change in temperature in degrees Celsius. This is because a change of 1 °C is equivalent to a change of 1 K: $\Delta T(K) = \Delta T(°C)$

3. Analysis and Detail

1. For the temperature change in degrees Celsius: $\Delta T(°C) = 100 \, \text{°C} - 30 \, \text{°C} = 70 \, \text{°C}$

2. For the temperature change in kelvins: $\Delta T(K) = \Delta T(°C) = 70 \, K$

4. Verify and Summarize

The calculations show that the change in temperature from $30 \, \text{°C}$ to $100 \, \text{°C}$ results in a difference of $70$ degrees in both Celsius and Kelvin.

Final Answer

i) The change in temperature is $70 \, \text{°C}$.
ii) The change in temperature is $70 \, K$.