Which one of the following interval(s) is the set solution of the quadratic inequality 10x2 – 4x – 6 < 8x2 + 4x – 12?a.(-∞,1) U (3, ∞)b.(-∞,1)c.(1, 3)d.(3, ∞)
Question
Solution 1
To solve the quadratic inequality 10x^2 – 4x – 6 < 8x^2 + 4x – 12, we first need to bring all terms to one side of the inequality.
Subtract 8x^2, add 4x and add 12 to both sides to get:
2x^2 - 8x + 6 < 0
Next, we factor the quadratic expression:
2(x - 1)(x - 3) < 0
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