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Which graph represents the piecewise equationsy=5+x𝑦=5+𝑥    (0≤x<5)(0≤𝑥<5)y=2x𝑦=2𝑥    (5≤x≤7)(5≤𝑥≤7)

Question

Which graph represents the piecewise equations

y=5+x(0x<5) y = 5 + x \quad (0 \leq x < 5) \quad
y=2x(5x7) y = 2x \quad (5 \leq x \leq 7) \quad

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Solution

To analyze the piecewise function given by the equations, we can break down the two equations and their corresponding domains:

  1. First Piece:

    • Equation: y=5+x y = 5 + x
    • Domain: 0x<5 0 \leq x < 5
  2. Second Piece:

    • Equation: y=2x y = 2x
    • Domain: 5x7 5 \leq x \leq 7

Steps to Graph the Piecewise Function

  1. Graph the First Piece:

    • For 0x<5 0 \leq x < 5 :
      • When x=0 x = 0 : y=5+0=5 y = 5 + 0 = 5
      • When x=4.9 x = 4.9 : y=5+4.9=9.9 y = 5 + 4.9 = 9.9 (approaches but does not include x=5 x = 5 )
      • When x=5 x = 5 : Not included in this piece.
    • Plot the line segment starting from the point (0, 5) to just below the point (5, 10).
  2. Graph the Second Piece:

    • For 5x7 5 \leq x \leq 7 :
      • When x=5 x = 5 : y=2×5=10 y = 2 \times 5 = 10
      • When x=6 x = 6 : y=2×6=12 y = 2 \times 6 = 12
      • When x=7 x = 7 : y=2×7=14 y = 2 \times 7 = 14
    • Plot the line segment connecting (5, 10) to (7, 14), including both endpoints.

Analysis and Pattern

  • The first piece y=5+x y = 5 + x is a straight line with a positive slope, starting from (0, 5) and increasing.
  • The second piece y=2x y = 2x also has a positive slope, starting from (5, 10) and continuing to (7, 14).

Verification and Conclusion

  • Each piece is continuous in its respective domain. At x=5 x = 5 , the left-hand limit approaches 10 10 from the first piece, matching the value for the second piece.
  • The lines should be drawn in separate segments to accurately represent the piecewise nature.

In summary, the correct graph will consist of:

  • A line segment starting from (0, 5) to just below (5, 10).
  • A line segment starting from (5, 10) and including (7, 14).

Final Answer

The graph representing the given piecewise function consists of two segments:

  • From (0,5) (0, 5) to just below (5,10) (5, 10) for y=5+x y = 5 + x .
  • From (5,10) (5, 10) to (7,14) (7, 14) for y=2x y = 2x .

This problem has been solved

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