What least number must be added to 1064 to get a number exactly divisible by 27?
Question
What least number must be added to 1064 to get a number exactly divisible by 27?
Solution
Step 1: Divide 1064 by 27.
1064 ÷ 27 = 39.40740740740741
Step 2: Round up the quotient to the nearest whole number.
The nearest whole number to 39.40740740740741 is 40.
Step 3: Multiply this whole number by 27.
40 x 27 = 1080
Step 4: Subtract the original number from this result.
1080 - 1064 = 16
So, the least number that must be added to 1064 to get a number exactly divisible by 27 is 16.
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