Which is a solution of the inequality 2x + 3y > 6?*(2, 1)(-3, 0)(-3, -4)(-2, 3)

To find out which pair is a solution to the inequality 2x + 3y > 6, we need to substitute each pair of (x, y) into the inequality and see if the inequality holds true.

1. For (2, 1), substituting x = 2 and y = 1 into the inequality, we get 22 + 31 = 4 + 3 = 7, which is greater than 6. So, (2, 1) is a solution.

2. For (-3, 0), substituting x = -3 and y = 0 into the inequality, we get 2*-3 + 3*0 = -6 + 0 = -6, which is not greater than 6. So, (-3, 0) is not a solution.

3. For (-3, -4), substituting x = -3 and y = -4 into the inequality, we get 2*-3 + 3*-4 = -6 -12 = -18, which is not greater than 6. So, (-3, -4) is not a solution.

4. For (-2, 3), substituting x = -2 and y = 3 into the inequality, we get 2*-2 + 3*3 = -4 + 9 = 5, which is not greater than 6. So, (-2, 3) is not a solution.

Therefore, the only solution to the inequality 2x + 3y > 6 from the given options is (2, 1).