Let! 1 2 3 ...n n=     i.e. product of firstn natural numbers. The HCF and LCM of 7! and8! are:

Question

Let! 1 2 3 ...n n= $\times \times \times \times$ i.e. product of first n natural numbers.

The HCF and LCM of 7! and 8! are:

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Solution

The HCF (Highest Common Factor) of two numbers is the largest number that divides both of them without leaving a remainder. In this case, 7! (factorial) is a factor of 8! (because 8! = 8 * 7!), so the HCF of 7! and 8! is 7!.

The LCM (Least Common Multiple) of two numbers is the smallest number that is a multiple of both of them. Since 8! is a multiple of 7!, the LCM of 7! and 8! is 8!.

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Let! 1 2 3 ...n n=     i.e. product of firstn natural numbers. The HCF and LCM of 7! and8! are:

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Let! 1 2 3 ...n n= $\times \times \times \times$ i.e. product of first n natural numbers.