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Express cot 85° + cos 75° in terms of trigonometric ratios of angles between 0° and 45°.

Question

Express cot 85° + cos 75° in terms of trigonometric ratios of angles between 0° and 45°.

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Solution

To express cot85+cos75 \cot 85^\circ + \cos 75^\circ in terms of trigonometric ratios of angles between 0 0^\circ and 45 45^\circ , we will utilize trigonometric identities.

Step 1: Break Down the Problem

We need to express cot85 \cot 85^\circ and cos75 \cos 75^\circ in terms of angles less than 45 45^\circ .

Step 2: Relevant Concepts

  1. Cotangent Identity: cot(90x)=tan(x) \cot(90^\circ - x) = \tan(x)
  2. Cosine Identity: cos(90x)=sin(x) \cos(90^\circ - x) = \sin(x)

Step 3: Analyze and Detail

  1. Calculate cot85 \cot 85^\circ : cot85=tan(9085)=tan5 \cot 85^\circ = \tan(90^\circ - 85^\circ) = \tan 5^\circ

  2. Calculate cos75 \cos 75^\circ : cos75=sin(9075)=sin15 \cos 75^\circ = \sin(90^\circ - 75^\circ) = \sin 15^\circ

Therefore, we can rewrite the expression: cot85+cos75=tan5+sin15 \cot 85^\circ + \cos 75^\circ = \tan 5^\circ + \sin 15^\circ

Step 4: Verify and Summarize

The expressions tan5 \tan 5^\circ and sin15 \sin 15^\circ are both in the range of angles between 0 0^\circ and 45 45^\circ .

Final Answer

Thus, the final expression is: tan5+sin15 \tan 5^\circ + \sin 15^\circ

This problem has been solved

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