The least number which when divided by 4, 6, 8, 12 and 16 leaves a remainder of 2 in each case is46485056None of these
Question
The least number which when divided by 4, 6, 8, 12 and 16 leaves a remainder of 2 in each case is
4648
5056
None of these
Solution
The least number which leaves a remainder of 2 when divided by 4, 6, 8, 12, and 16 is found by first determining the least common multiple (LCM) of these numbers and then adding the remainder to it.
Step 1: Find the LCM of 4, 6, 8, 12, and 16. The LCM of these numbers is 48.
Step 2: Add the remainder to the LCM. The remainder in this case is 2. So, 48 + 2 = 50.
Therefore, the least number which when divided by 4, 6, 8, 12 and 16 leaves a remainder of 2 in each case is 50. So, the answer is "None of these" as 50 is not listed in the options.
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