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Two bodies of equal weight are kept at heights 'h' and '3h' respectively. The ratio of their PE is

Question

Two bodies of equal weight are kept at heights 'h' and '3h' respectively. The ratio of their PE is

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Solution

To find the ratio of the potential energy (PE) of the two bodies, we can use the formula for gravitational potential energy:

PE = mgh

where PE is the potential energy, m is the mass of the body, g is the acceleration due to gravity, and h is the height.

Let's assume that the mass of both bodies is equal, so we can cancel out the mass term in the ratio. Therefore, we only need to compare the heights.

The first body is at a height of 'h', and the second body is at a height of '3h'.

Now, let's calculate the potential energy for each body:

PE1 = mgh PE1 = mgh

PE2 = mgh PE2 = mgh

Since the mass and acceleration due to gravity are the same for both bodies, we can cancel them out as well.

Therefore, the ratio of their potential energies is:

PE1/PE2 = (gh)/(3gh) PE1/PE2 = 1/3

So, the ratio of their potential energies is 1:3.

This problem has been solved

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