A POINT MOVES ON A PARABOLA y²=8x IN SUCH A WAY THAT THE RATE OF CHANGE IS ALWAYS 5 units/sec HOW FAST IS THE ABSCISSA CHANGING WHEN THE ORDINATE IS 4
Question
Solution 1
Given the equation of the parabola is y² = 8x.
We can differentiate both sides with respect to time (t) to find the rate of change of x with respect to time (dx/dt).
Using the chain rule, the derivative of y² with respect to t is 2y(dy/dt) and the derivative of 8x with respect to t is 8(dx/dt).
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