In digging a pond there got a bone, which has 80% of its initial carbon14. Using ✓ carbon decay model find the age of the bone.

The Carbon-14 decay model is represented by the equation:

N = N0 * e^(-0.000121 * t)

Where:

• N is the final amount of Carbon-14
• N0 is the initial amount of Carbon-14
• t is the time in years
• 0.000121 is the decay constant for Carbon-14

In this case, we know that N is 80% of N0. So we can set up the equation as follows:

0.8N0 = N0 * e^(-0.000121 * t)

We can simplify this by dividing both sides by N0:

0.8 = e^(-0.000121 * t)

To solve for t, we'll need to use natural logarithms. The equation becomes:

ln(0.8) = -0.000121 * t

Solving for t gives:

t = ln(0.8) / -0.000121

Using a calculator, we find that t is approximately 2230 years. So the bone is approximately 2230 years old.