Self condensation of two moles of ethyl acetate in presence of sodium ethoxide yieldsacetoacetic estermethyl acetoacetateethyl propionateethyl butyrate

The self-condensation of two moles of ethyl acetate in the presence of sodium ethoxide yields acetoacetic ester. Here's the step-by-step process:

1. Sodium ethoxide acts as a base and deprotonates the alpha hydrogen of one of the ethyl acetate molecules. This forms a carbanion.

2. This carbanion then attacks the carbonyl carbon of the second ethyl acetate molecule. This forms a tetrahedral intermediate.

3. The tetrahedral intermediate then collapses, kicking out the ethoxide ion and forming a new carbon-carbon bond.

4. The ethoxide ion then deprotonates the alpha hydrogen of the newly formed molecule, forming a carbanion.

5. This carbanion then attacks the carbonyl carbon of the same molecule, forming a five-membered ring. This is the acetoacetic ester.

So, the correct answer is acetoacetic ester.