How many moles in 22.81 mL of liquid mercury (Hg)? Answer to 3 decimal places.𝜌(Hg) = 13.534 g.mL-1MW(Hg) = 200.59 g.mol-1

1. Break Down the Problem

To find the number of moles of liquid mercury (Hg) in 22.81 mL, we need to:

1. Calculate the mass of mercury using the density.
2. Convert the mass to moles using the molar mass.

2. Relevant Concepts

The relevant formulas are:

• Mass = Volume × Density
• Moles = Mass / Molar Mass

3. Analysis and Detail

1. Calculate the Mass of Mercury: $\text{Mass} = \text{Volume} \times \text{Density}$ Given: $\text{Volume} = 22.81 \, \text{mL}$ $\text{Density} = 13.534 \, \text{g/mL}$

   $\text{Mass} = 22.81 \, \text{mL} \times 13.534 \, \text{g/mL} = 308.06734 \, \text{g}$

2. Calculate the Number of Moles: $\text{Moles} = \frac{\text{Mass}}{\text{Molar Mass}}$ Given: $\text{Molar Mass} = 200.59 \, \text{g/mol}$

   $\text{Moles} = \frac{308.06734 \, \text{g}}{200.59 \, \text{g/mol}} \approx 1.535$

4. Verify and Summarize

We calculated the mass of mercury and subsequently the number of moles. The calculations followed the standard formulas, and the values inserted were accurate.

Final Answer

The number of moles in 22.81 mL of liquid mercury (Hg) is approximately 1.535 moles.