A 60 μF capacitor is connected to a 110 V, 60 Hz AC supply. Determine the rmsvalue of currenct in the circuit.
Question
A 60 μF capacitor is connected to a 110 V, 60 Hz AC supply. Determine the rms value of current in the circuit.
Solution
To determine the rms value of current in the circuit, we can follow these steps:
Step 1: Calculate the angular frequency (ω) of the AC supply using the formula: ω = 2πf where f is the frequency of the AC supply (60 Hz).
ω = 2π * 60 ω ≈ 377 rad/s
Step 2: Calculate the capacitive reactance (Xc) using the formula: Xc = 1 / (2πfC) where C is the capacitance (60 μF).
Xc = 1 / (2π * 60 * 60 * 10^-6) Xc ≈ 44.18 Ω
Step 3: Calculate the rms value of current (Irms) using Ohm's Law: Irms = Vrms / Xc where Vrms is the rms value of voltage in the circuit (110 V).
Irms = 110 / 44.18 Irms ≈ 2.49 A
Therefore, the rms value of current in the circuit is approximately 2.49 A.
Similar Questions
A 10-µF capacitor is plugged into a 110 V-rms 60-Hz voltage source, with an ammeter in series. What is the rms value of the current through the capacitor?
A capacitor has a capacitive reactance of 22 Ω when connected across a 120 V, 60 Hz supply. Calculate the capacitance in microfarads.
The peak value of A.C source is 20 A, its rms value will be:A. 14.1 A ⃝ B. 10 A ⃝C. 20 A ⃝ D. 28.2 A
An alternating voltage is given by v = 282.8 sin 314t volts. Find (a) the rms voltage
A 60-Hz ac generator with a peak voltage of 110 V drives a series RC circuit with R=10.0 and C=300mF The peak current in the circuit is
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.