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A 60 μF capacitor is connected to a 110 V, 60 Hz AC supply. Determine the rmsvalue of currenct in the circuit.

Question

A 60 μF capacitor is connected to a 110 V, 60 Hz AC supply. Determine the rms value of current in the circuit.

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Solution

To determine the rms value of current in the circuit, we can follow these steps:

Step 1: Calculate the angular frequency (ω) of the AC supply using the formula: ω = 2πf where f is the frequency of the AC supply (60 Hz).

ω = 2π * 60 ω ≈ 377 rad/s

Step 2: Calculate the capacitive reactance (Xc) using the formula: Xc = 1 / (2πfC) where C is the capacitance (60 μF).

Xc = 1 / (2π * 60 * 60 * 10^-6) Xc ≈ 44.18 Ω

Step 3: Calculate the rms value of current (Irms) using Ohm's Law: Irms = Vrms / Xc where Vrms is the rms value of voltage in the circuit (110 V).

Irms = 110 / 44.18 Irms ≈ 2.49 A

Therefore, the rms value of current in the circuit is approximately 2.49 A.

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