What value will EAX contain after the following instructions execute?.datadVal DWORD 12345678h.codemov ax, 3mov WORD PTR dVal+2, axmov eax, dVal

The instructions are written in Assembly language. Here's a step-by-step explanation:

1. mov ax, 3: This instruction moves the value 3 into the AX register. AX is the lower 16 bits of the EAX register.

2. mov WORD PTR dVal+2, ax: This instruction moves the value in AX (which is 3) into the memory location at dVal+2. Since dVal is a DWORD (32 bits or 4 bytes), dVal+2 refers to the third and fourth bytes of dVal. The original value of dVal is 12345678h (in hexadecimal), which in binary is 0001 0010 0011 0100 0101 0110 0111 1000. The third and fourth bytes are 0101 0110 0111 1000, which will be replaced by 0000 0000 0000 0011 (the binary representation of 3).

3. mov eax, dVal: This instruction moves the value in dVal into the EAX register. After the second instruction, dVal is 0001 0010 0000 0000 0000 0011, which in hexadecimal is 120003h.

So, after these instructions execute, EAX will contain the value 120003h.