Tap A alone fills a tank in 24 hours. Tap A and tap B together fill the same tank in 15 hours. Tap B alone can fill the tank in how many hours?
Question
Tap A alone fills a tank in 24 hours.
Tap A and tap B together fill the same tank in 15 hours.
Tap B alone can fill the tank in how many hours?
Solution
Step 1: Determine the rate at which Tap A fills the tank. Since Tap A can fill the tank in 24 hours, its rate is 1/24 of the tank per hour.
Step 2: Determine the combined rate of Tap A and Tap B. Since they can fill the tank together in 15 hours, their combined rate is 1/15 of the tank per hour.
Step 3: Subtract the rate of Tap A from the combined rate of Tap A and Tap B to find the rate of Tap B. This is 1/15 - 1/24 = 9/360 = 1/40 of the tank per hour.
Step 4: Since the rate of Tap B is 1/40 of the tank per hour, it would take Tap B 40 hours to fill the tank on its own.
Similar Questions
5 identical taps can fill a tank in 21 minutes.How long will it take 7 such taps to fill the same tank? minutes
9 pipes are required to fill a tank in 4 hours. How long will it take if 12 pipes of the same type are used?Choices:-
If three taps are open together, a tank is filled in 10 h. one of the taps can fill in 5 h and another in 10 h. at what rate does the 3rd pipe work?
3 pumps, working 8 hours a day, can empty a tank in 2 days. How many hours a day must 4 pumps work to empty the tank in 1 day?
A and B together can do a piece of work in 8 days, but A alone can do it in 12 days. How manydays would B alone take to do the same work?
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.