Consider this recurrence relation: T(1) = 1 T(2) = 1 T(n) = 4 T(n-2) + 2n2 for n>2 The Master Theorem tells us Group of answer choices
Question
Consider this recurrence relation:
T(1) = 1
T(2) = 1
T(n) = 4 T(n-2) + 2n^2 for n > 2
The Master Theorem tells us
Group of answer choices
Solution
The Master Theorem provides a method for analyzing the time complexity of recurrence relations of the form:
where and . However, the recurrence relation you've given does not fit this form directly since the recursive call is based on rather than dividing .
To analyze this recurrence, we can use substitution or expansion to find a pattern. Here are the steps for doing so:
-
Break Down the Problem
We have the recurrence: with initial conditions and . -
Relevant Concepts
We will expand the recurrence to express in terms of previous values: We can substitute based on the same form: -
Analysis and Detail
Substituting back into the original equation iteratively:- First substitute :
- Now substitute further:
Continuing this substitution until reaching the base cases leads to identifying how many terms will contribute to .
-
Verify and Summarize
We can explore the pattern. Each recursive step effectively adds terms of the form with a multiplying factor increasing by 4 for each step back. It will be complex without exact forms so setting bounds directly might be easier.Ultimately, recognizing that this generates a quadratic sum leads to overall polynomial growth.
Final Answer
The recurrence grows as we recursively apply the relation, indicating a non-linear polynomial time complexity, roughly of the order when approximated through expansion and verifying dominating terms in calculations. However, without a straightforward fit to the Master Theorem or an explicit coefficient identification, it may require deeper methods (like generating functions) for a concrete exact closed form. Thus, identify that growth resembles cubic behavior due to iterated summing of quadratic contributions.
Similar Questions
Consider this recurrence relation: T(1) = 1 T(n) = 2 T(n/3) + 2n + 1 for n>1 The Master Theorem says that T(n)∈ Θ()?
Select the correct recurrence relation for Tower of Hanoi?ans.T(n)= 2T(n-1)+1T(n)= 2T(n-1)+2T(n)= 2T(n)+1T(n)= 2T(n-2)+2 Previous Marked for Review Next
Explain master theorem and solve the recurrence T(n)=9T(n/3)+n with master method.
Consider the following recurrence relation for a function T(n):T(n) = 3T(n/2) + nUse the recursion tree method to determine the time complexity of T(n)
What is the recurrence relation for the linear search recursive algorithm?T(n-2)+c2T(n-1)+cT(n-1)+cT(n+1)+c
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.