A function f : A B defined as f(x) = 2x is both one-one and onto. IfA = {1, 2, 3, 4}, then find the set B.

f: R+→R defined by f (x)=2x, x∈ (0,1), f (x) = 3x, x∈ [1,∞) is one -one, onto neither one-one nor onto  one-one, not onto onto

Show that the function f:N→N, given by f(1)=f(2)=1 and f(x)=x−1 for every x>2, is onto but not one-one.Easy

If f : R → R be defined as f(x) = 𝑥4,then the function f isa) one-one and onto b) many-oneandontoc) one-one but not onto d ) neither one-one nor ont

If R denotes the set of all real numbers then the function f : R → R defined f (x) = [x] isOne-one onlyOnto onlyBoth one-one and ontoNeither one-one nor onto

The function f(x)=x+1 from the set of integers to itself is onto. Is it True or False?