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The electric field of an electromagnetic wave in free space is represented as E⃗ =E0cos(ωt−kz)iˆ.The corresponding magnetic induction vector will be :

Question

The electric field of an electromagnetic wave in free space is represented as

E=E0cos(ωtkz)i^ \vec{E} = E_0 \cos(\omega t - kz) \hat{i}

The corresponding magnetic induction vector will be :

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Solution

The magnetic field (B) of an electromagnetic wave in free space is always perpendicular to the electric field (E) and can be found using the relation B = E/c, where c is the speed of light in vacuum.

Given the electric field E = E0cos(ωt−kz)i, the magnetic field will have the same phase but will be in the j direction (since E and B are perpendicular) and its magnitude will be E0/c.

So, the magnetic field B can be represented as B = (E0/c)cos(ωt−kz)j.

This problem has been solved

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