n C, what is the result of declaring a pointer as int *ptr; without initialization?
Question
Solution 1
When you declare a pointer in C using int *ptr; without initialization, the pointer ptr is likely to point to some random memory location, which can be any location in the memory of your computer. This is because, in C, local variables are not initialized by default. This could potentially lead
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n C, what is the result of declaring a pointer as int *ptr; without initialization?
In C, what is the result of declaring a pointer as int *ptr; without initialization?
ct the correct answerWhich of the following is the correct way to declare a pointer to an integer in C?Optionsinteger *ptr;ptr *int;int *ptr;point int *ptr;
ect the correct answerHow do you declare a constant pointer to an integer in C?Optionsint *const ptr;const int *const ptr;const int *ptr;int const *const ptr;
What will you see on the terminal?int main(void){ int *ptr; *ptr = 98; printf("%d\n", *ptr); return (0);}