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2. Draw an acute-angled ∆PQR. Draw all of its altitudes. Name the point of concurrence as ‘O’.

Question

2. Draw an acute-angled ∆PQR.

  • Draw all of its altitudes.
  • Name the point of concurrence as ‘O’.
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Solution

Step 1: Draw a triangle PQR with an acute angle. You can use a ruler and a protractor to ensure the angles are less than 90 degrees.

Step 2: Draw the altitude from each vertex. The altitude of a triangle is a line segment from a vertex of the triangle to the line containing the opposite side, and it's perpendicular to that line.

  • To draw the altitude from vertex P, extend the line QR (if necessary) and draw a line from P to this extended line such that it forms a 90-degree angle with QR.
  • Repeat this process for vertices Q and R.

Step 3: The point where all three altitudes intersect is the orthocenter of the triangle. Label this point as 'O'.

Remember, in an acute-angled triangle like ∆PQR, the orthocenter 'O' will always be inside the triangle.

This problem has been solved

Similar Questions

4. Draw an obtuse-angled ∆LMN. Draw its altitudes and denote the orthocenter by ‘O’.

6. Draw an isosceles triangle. Draw all of its medians and altitudes. Write your observation about their points of concurrence.

1. In ∆LMN, …… is an altitude and …… is a median. (Write the names of appropriate segments.)

3. Will an altitude always lie in the interior of a triangle? If you think that this need not betrue, draw a rough sketch to show such a case

The orthocenter is Blank 1 Question 17 of the the triangle, in an obtuse triangle.

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